§1. Solving heat flow problems in the real world [00:04]
I want to talk about heat flow. We talked about heat flow in welding, but now I want to talk about how you really solve heat flow problems in the real world. I did the minor for my doctoral thesis on heat and fluid flow. I took graduate courses in mechanical — boiling water heat transfer, nuclear reactor heat transfer, which people were really interested in at that time. And then I took courses over in the math department in building two on all the math. It's great to give you a quiz — I could ask you to solve some partial differential equation, and you could regurgitate back what they had regurgitated to you. Sometimes it came out in a similar form, sometimes it didn't.
But in practice as an engineer, I learned that that's not how I solve heat flow problems. And I have to worry about heat flow problems all the time. Sometimes you need to do a finite element analysis, which is a lot easier to do today than it used to be. But most of the time — and by most of the time I mean ninety-five percent of the time — you don't need to do the heat flow analysis. You can just do a back-of-the-envelope calculation with the Fourier number.
Fourier's second law comes out of the first law. Fourier's first law just says, if I've got temperature and distance, the heat flows down the temperature gradient, and you get a steady state. In Cartesian coordinates it should be a straight line as long as the thermal conductivity doesn't change. J, the heat flux, is minus K dT/dx in one dimension. Heat in equals heat out, it's steady state, you get a uniform profile. If you go to cylindrical coordinate systems, you'll get something with curvature, because your area is changing as you go out radially. Things do change in different coordinate systems, and there are whole textbooks that take Fourier's first law into Fourier's second law.
Fourier's second law says, let's have more heat coming in than going out, and how does heat accumulate, and how does temperature change with time. The change in temperature with time in a little volume element is equal to K — and you have to have heat capacity and density, so you know how much you have. You can heat up a foam faster than you can a solid material of the same composition, right. So you have to have density and heat capacity, and the second derivative of temperature with distance, which is the curvature. If I have heat coming in faster, by Fourier's first law I have to have a steeper temperature gradient, and even in Cartesian coordinates I'll get a curved line for Fourier's second law. But it changes with time — it's not steady state.
K over rho C sub P is defined as the thermal diffusivity. This turns out to be a diffusion equation. That's what I took over in the math department — the mathematics of diffusion equations. There are whole books on it. It doesn't matter — this is heat diffusion, but you can also look at this as mass diffusion: change in concentration with time equals the mass diffusivity times the square of the concentration gradient with x. If you're a mathematician, grad T equals K over rho C sub P grad squared T. So, are they teaching you how to solve these types of equations now? Isn't it fun? If you don't learn how to regurgitate it, that doesn't mean you have to understand it.
Well, no one bothered to teach me that all you really need is the argument here. You can show mathematically — and they taught me over in the math department — that you can do a dimensional analysis on this, and whatever solution you have, whether it's an error function solution, an exponential, a Bessel function in cylindrical coordinates, Bessel function in spherical coordinates — all these fancy things that go into the big textbooks for different geometries and coordinate systems — they always have an argument of the exponent or the Bessel function in terms of a dimensionless number. In this case it's called the Fourier number for heat transfer. For mass diffusion it's called the Fick number. And it's x over the square root of Dt, where D is mass diffusivity, as opposed to alpha for thermal diffusivity.
Alpha has units of centimeters squared per second. We already know certain things. Copper has very good thermal diffusivity — it's about one centimeter squared per second. Aluminum is forty percent less but still very good. Iron is 0.1, stainless steel is 0.05, titanium is 0.05. Stainless steel and titanium are considered lousy thermal conductors as metals go. Ceramics can be 0.02 to 0.05. Insulating foams might be a hundredth, or maybe ten-to-the-minus-five. There's only about three orders of magnitude difference between foam insulators and copper, which turns out to have one of the highest thermal diffusivities of anything.
Silver has a thermal conductivity of about 1.2. Thermal conductivity is different than thermal diffusivity. Most people don't tabulate thermal diffusivity because it's a derived quantity from these three more fundamental quantities, so usually you have to calculate it. The only text I know — I put a table in the welding handbook, because in welding we're always dealing with transient heat flow problems. Steve will tell you, I don't like to solve equations or do finite element analyses myself. But I can just take the Fourier number, and I can solve ninety-five percent of all real engineering problems — not homework problems — with this simple little formula.
Einstein, I think, was the first one to prove mathematically that you always get an argument of x over the square root of the diffusivity times time. If this is centimeters squared per second, this is time in seconds, this is the square root of centimeters squared which is centimeters, and the whole thing is dimensionless. If you're a chemical engineer, they love to study dimensionless numbers in fluid flow and heat flow. There is also a diffusivity for viscosity, but because you have convection in fluids it gets really messy, and it's called the Navier-Stokes equation — it's got a lot more terms. It's basically looking at how shear stresses diffuse through the system in fluid flow. There are whole courses on Navier-Stokes.
But in fact, all you really need to know in heat flow ninety-five percent of the time is whether you're infinitely thick, sufficiently thin that you end up with no large temperature gradients, or somewhere in between. It's only five percent of the time that you're somewhere in between and have to go do the fancier analysis. For a Fourier number of one, you're basically in the situation where the distance the heat travels divided by the speed at which it travels is a similar ratio. If these are the boundaries of my system, the heat is starting to go from one surface and accumulate on the other. If I want to know anything with real precision, I need to solve the whole equation. But that involves solving a differential equation — that's something you give to a graduate student. That's not something a faculty member does. You graduate beyond that.
In a thick-section solution, the thing is so thick that the heat coming in doesn't get anywhere near the other edge. You can treat it as an infinitely thick solution, and use this number to figure out approximately the distance the heat flows into the material. For a Fourier number of a tenth, the heat has started to accumulate on the other surface and flatten out the gradient, which slows down heat transfer into the material — because by Fourier's first law that gradient is the rate of heat coming in. When you first put a cold thing into an oven, the heat going in is very rapid. As it warms up, the heat going in decreases over time because the gradient at the surface decreases.
You do have to worry about different geometries — convergent heat flow and divergent heat flow. In convergent heat flow, I'm heating on the outside of a surface with a smaller surface on the inside — I might be heating the outside of a tube. I'll heat up faster because I have a smaller area to accumulate the heat in. In divergent heat flow, I'm heating on the inside of a tube or a sphere, and I have to heat up a greater mass out here. The area is decreasing as 1/r in convergent, increasing as 1/r in divergent; in a sphere it's 1/r² either way. Convergent will be faster heating, divergent will be slower. In most cases it's maybe a factor of two difference. But in a lot of cases I don't even care about a factor of two — I just want to know, did I heat all the way through, or did I barely touch the surface.
§2. The forging press repair: a heat-flow object lesson [12:55]
To give you some examples of what you can get out of this. If I want to calculate the width of the heat-affected zone in steel from an arc weld, I say the width is going to be on the order of the square root of alpha T. The interaction time for the heat source as it travels along — remember, I showed you the fancy heat flow analysis with the traveling point heat source. The arc weld pool is about one centimeter long because one's a convenient number. The interaction time is one centimeter divided by velocity. A typical arc weld might go at half a centimeter per second. For steel, alpha is 0.1 centimeters squared per second. Times 2, square root of 2 is about 1.4, and so on — you get about 0.4 centimeters, which is four millimeters.
So the width of the heat-affected zone in steel should be on the order of four millimeters for a typical arc weld. [Tom passes a welded sample around the class.] Anybody know what four millimeters is? About 3/16 of an inch, a little under. Look at that heat-affected zone — it's about 3/16 of an inch. If I want to know whether the heat-affected zone is one millimeter or ten millimeters, I can go through a simple little analysis like this. All I had to do was figure out my interaction time and take Fourier's law, and I come up with a number that's reasonably close.
Now, remember I brought in this 12- or 13-inch-thick weld with hundreds of weld passes — it weighed about ten pounds when I passed it around. That's one where they had to preheat the metal. About 12 inches of steel — well, 12 inches isn't 30 centimeters, that's 10 inches, but it's close to 30 centimeters; I'm rounding because this is an approximate analysis. Here's the Fourier number — x squared, the distance the heat travels, is alpha T. Square 30, I get 900, divide by a tenth which is alpha, the time is 9000 seconds, which is two and a half hours. Well, that's why that weld cracked. The section I showed you wasn't cracked, but they lost about a five million dollar press because they'd been using this forging press for fifty years. Over time it wore out, developed a fatigue crack, and cracked.
They decided, okay, we're going to repair-weld it. So they brought in these good-old-boys welders. They had never taken a heat-flow course — they weren't welding engineers, they were welders. They knew you were supposed to preheat the steel, and they were used to using flame torches or electric blankets. But they didn't know how heat flow changes when you go from one inch thick to ten or twelve inches thick. While you can heat that one-inch piece for five or ten minutes to get the heat to soak through, a 12-inch piece you have to heat for two and a half hours. So they heated for 10 or 12 minutes — that was their standard procedure — they started welding, and guess what: they were welding on unpreheated steel. They got tremendous residual stresses, hydrogen embrittlement, and cracking.
So they decided, we'll just do it again. What's the definition of stupidity? Doing the same thing over and over expecting a different result. So they did it again, and it cracked again. Actually the first time it cracked right away as it was cooling down — they heard bang, and a crack propagated. The next time they gouged it out and decided they needed a full penetration weld instead of a partial penetration weld, which is what you actually see in the sample. This one survived — it was holding together, no cracks. So they put it on the press, and the first time they loaded it, because of the significant residual stresses — they did no stress relief — wham, crack. At that point they just scrapped the whole press. Used, it's only about a five million dollar press, but it's destroyed. To buy a new one is probably about 50 million dollars. So there are a lot of problems with people not understanding heat flow and preheating. In welding metallurgy we'll talk a little bit about preheating, which is in one of your reading modules.
§3. Temper bead welding and the spot weld electrode case [18:30]
Student: [Asks whether Tom is calculating the heat-affected zone width.]
Yes — approximately.
It depends on the situation. Just because I can calculate it doesn't mean I should. There are times when you want to know the size of the heat-affected zone. In certain boiler steels you actually want to use the top pass in a multi-pass weld to temper the bottom pass — we call it temper bead welding. I'm going to make some heavy-section joint in a pressure vessel — call it chrome-moly steel. In chrome-moly steels you would like the bead to be tempered, because chrome-moly will form hard martensitic steel if it isn't. So this bead will have a heat-affected zone like this.
In many heat-treated steels you would like the heat-affected zone around a weld to temper the bead underneath. If the heat-affected zone is too narrow, I don't temper the full bead. So what size pass can I put in? A lot of times you're limited in pass size in pressure vessel seals because I want a heat-affected zone that will encompass the bead underneath. I can't just pour the heat in. I'm trying to do metallurgical heat treatment with the pass above. Sometimes they'll put a cap pass on, which they'll grind off — put them on and grind them off — so you've tempered everything beneath.
It's not just heat-affected zones. Several of your homework problems, if you choose to do them in chapter 16, are calculating things like this. One of them: resistance spot welding electrodes. A resistance spot welding electrode is a copper electrode, water-cooled on the inside, with a piece of steel between two copper electrodes. You might pass 10,000 amps through the copper electrodes for a third of a second. Copper has thermal diffusivity of one. You've got a third of a second. During the time of the weld, is the water cooling here effective in cooling the tip, or not?
Student: [Suggests cooling happens between welds rather than during.]
Yes, you've got the cycle between welds, and you definitely will cool — there's like two or three seconds between welds. To give you a real-world example, and one of the ways I've used this. About 1985, they were welding galvanized steel in the automotive industry. Terrible problems. They used to weld non-zinc-coated steels, because they didn't care if your car rusted out in three years — you'd have to buy a new one. But after the 1972 oil embargo, the goal was to have cars with no rust for seven years. They started giving warranties to that effect and were losing their shirts. So they started galvanizing the steel, putting a zinc coating on as a sacrificial anode.
They had problems because the zinc was alloying with the copper, creating a high-resistance interface. Ford had a spec: you had to have 2,000 welds before you had to change the copper tips. Why 2,000? Because the robots making the welds would go for about two and a half hours between shifts until shutdown so maintenance could come and change the tips. A hundred welds is like ten minutes. You're going to shut down an automotive line that's turning out one car a minute — five thousand dollars, ten thousand dollars profit per minute. Every minute of shutdown is lost profit. So they wanted something that only had to be changed during scheduled shutdown, halfway through the shift. That was 2,000 welds.
Ford had a spec of 2,000 welds. When they first started using galvanized steel they were getting 100 or 200 welds before the tips wore out. That's why I said you have to put two or three thousand spot welds in an average automobile — because you need 2,000 good ones and they're making a lot of bad ones. Some of these cars go through an accident and just unzip like a piece of paper on these spot welds. So someone came in and told Chrysler in the mid-1980s, for only fifty million dollars we will sell you a refrigeration unit that will chill the water in your copper tips, and it will improve your electrode life. No data — just, obviously if you chill the tips you're going to keep them from getting this hot.
You get to do the calculation. I did the calculation for the guys at Chrysler. I was doing other work for them, and they said, this guy's trying to sell us fifty million dollars worth of refrigeration to run chilled water through the plant — you think it'll do us any good? I said, no. They said, why not? I did Fourier's law right there in front of them. They didn't have a clue. I put an equation in front of them and their eyes glazed over. But I proved that during that one-third of a second, it doesn't matter whether you have water up there or not. Your point is correct — it cools off between the next weld, which might be two or three seconds later. If you put in three seconds instead of a third of a second, you'll find, yeah, I did cool the tip off in between.
But I pointed out another thing. Anybody have any idea of what the problem would be in an un-air-conditioned plant with chilled water running through copper tubes?
Student: Condensation.
Exactly. How would you like it raining on your unpainted — actually galvanized — steel automobile while you're trying to assemble it? I explained that if you put this in, you're going to take it out a week later. They said, can you prove this? I said, I just did — I did the calculation. But to them that's not proof, it's just a calculation, which means nothing. So they gave me a fifty-five thousand dollar research contract which I had to perform in three months. I didn't have time, so I gave most of it to one of my postdocs who was leaving to become a professor at another university in three months. I took about ten thousand because I had to go back to Chrysler and present this later.
We had to come up with a refrigeration unit for chilled water. You know how we did it? A fifty-five-gallon plastic trash can. We filled it with ice and water, put a copper coil in it, and ran the water through the ice water — chilled water. It wouldn't last forever, but there's plenty of ice in the ice machines at MIT. So we did the test, did some experiments, did the calculations, and for a mere fifty-five thousand dollars I convinced Chrysler not to spend fifty million dollars on water chillers because it would do them no good. We proved you would not get more than 100 or 200 good spots on your electrodes. But I knew it from the beginning. It's easy to take that money.
Carl, the postdoc, had been one of my doctoral students. He made thirty thousand dollars in three months, which was a down payment for a house when he moved to his new place. We hired a couple of undergraduates over the summer to do all the scutwork — sitting there making welds. Making 5,000 welds is really exciting. The students were happy, they made ten thousand dollars over the summer. Carl made thirty thousand, we had five thousand in expenses, and I made ten thousand for a few trips to tell Chrysler how stupid they were. But it's because I knew the Fourier number. They still wanted to spend the money — I couldn't prove it to them analytically, they wouldn't believe it.
§4. The Office of Naval Research consortium and the Laplace equation insight [28:40]
Student: [Asks how Tom became involved with the spot welding problem.]
We were doing other work for Chrysler on spot welding, which is why they asked me. There are other ways to do it well. I got research money out of Detroit for ten years on this problem. When it started in 1980, they were getting about 200 spots; by 1990 they were getting about 2,000. They changed some of the steel sheet surface — the galvanizing — and went to thinner gauge zinc. One of the more important things was that they decided to do maintenance on their tips and equipment. The big problem was, not that you couldn't get a thousand if everything was aligned — but if this came in skewed at an angle, so you're really making contact right at the edge, you get a real hot spot. That was destroying things — if you didn't put the tips on square.
Halfway through the 1980s I was being funded by General Motors, Ford, and International Lead Zinc — a little consortium. I'll tell you why. In 1980, the U.S. Navy Office of Naval Research decided, we've got someone at MIT who's interested in welding, we have welding problems, we're going to fund him. The Reagan administration started giving them more money but no new head count. So they had to give out bigger research contracts. The first place they did it was at Penn State, on sonar materials, piezoelectric ceramics. The second was MIT. They gave me at the time almost half a million dollars a year, which today would be like a two or three million dollar a year contract.
I gave Professor Hart in mechanical engineering — a new young assistant professor — his first research contract. I was told by ONR, we want you to find other people at MIT to bring in to think about welding problems. So I was going around giving away money. I was still barely an associate professor, and all of a sudden I had more research money than most of the full professors in the department. I started thumbing my nose at them, which didn't endear me to them, but I still got tenure. Then General Motors did something. I was funded by General Motors research, and Jamie Sue, who I have a lot of respect for, canceled the project. But it wasn't just me — he canceled all spot welding research at General Motors research. They did a study of the plants and found that out of 39 root cause problems, 35 were maintenance issues. The top ten were all maintenance issues. Jamie said, why should I be spending my research money to teach them how to make better spot welds if they're not going to maintain their equipment? And he was right.
So I lost my General Motors money for six months, until Buick-Oldsmobile-Cadillac — they reorganized all the time — one of the car divisions, as opposed to the research division, picked it up. They knew they had all kinds of problems and liked the work I'd done, so they wanted to fund it. They kept funding it, and Ford funded it, and International Lead Zinc funded it, and it kept going for a while.
Let me tell you one of the things we did. In spot welding of sheet steels — this is a process invented by Elihu Thompson, who had been a president of MIT, had 380 patents, helped co-found General Electric. They were using an angle here of about 15 degrees on the electrode tip. If your current is coming down through here, it has to come down like that, and if you think of flow lines, the current bunches up right at the corner. That's the same thing as a stress concentration. Mathematically, it's solving Laplace's equation. I'm from MIT, I know what differential equations are.
I would go to General Motors research, because they've heard of Laplace's equation — they don't know what to do with it, but they've heard of it. I said, that's the wrong angle — you should have a 45-degree angle on your electrode tips. Now the current doesn't bunch up as much, it's less of a current concentration. We sectioned things halfway through, we did high-speed infrared movies of this. If I could find them — it's probably all on VHS, I don't know if I have a VHS player anymore. At one time it was on the website, but I think it's been lost. We did high-speed movies, and you could see the hot spots from the maldistribution of current. By changing just the geometry of those copper tips, we got double the life.
I later found out there were companies Ford would hire to qualify the steel from steel suppliers. Steel suppliers had to meet 2,000 welds or Ford wouldn't buy from them. It was hard to pass 2,000 welds. What were they using in the plant? A 15-degree angle. What were they using to run the test? Part of the Ford spec — 45 degrees. 45 gave you better electrode life, but then you go in the plant and use the angle that gives you lousy electrode life. The mathematics is the same as a stress concentration — this is an electrical current concentration. It all comes out of Ragnar Holm in electrical contacts.
In any case — why do you do it, how do you do it. I don't run into this quite as often as I used to, but I used to have a couple of consulting projects with industry a year. Maybe still at least once a year. I'll be sitting in a meeting, someone's talking about some heat flow problem, and I'll do it in my head or scratch it out on paper, and I'll say, oh, this is the solution. They all look at me — how do you know? This is a complex heat flow problem. I said, yeah, I know, but I just solved it. It's not that complex an equation. I can do some of those in my head. X over square root of T. Sometimes I make mistakes because of the square root and all, but if you practice enough you can get it down. The real point is, there's tremendous ability in being able to estimate your solution before you go off and do fancy calculations.
§5. Why professors do derivations (an aside) [37:00]
So that's enough — that's my secret of heat transfer. I already gave you my secret of why professors do a derivation for a whole hour in class. Did I tell you that one? It's one of my favorites.
I learned this as a young first- or second-semester assistant professor. I had been on a trip, and I was teaching a graduate course on how to forge and roll and do all this other stuff. I got in that morning and, because I'd been on the trip, I really hadn't prepared my lecture very well. Class was coming up, so I looked in the book, and here was the derivation. I said, ah, I'll just do the derivation. And all of a sudden the light went off — I said, oh, that's why professors do derivations in class.
It's a time waster. For me the time waster is telling you stories. Doing a derivation on the board is less interesting than the stories. So I justified my stories as my time waster. But at that time I swore I would never do a derivation in class again, and I haven't. I taught thermo for years and I never did a derivation. I would write it out on a piece of paper ahead of time and hand it out to the students and say, you're MIT students, you went through algebra in high school, you can follow this derivation even if it's a differential equation. Differential equations are just using these D's and squiggly D's and stuff in algebraic form — there are a few other rules, but you're just manipulating abstract symbols. So I have never done a derivation in class since. I hand it out and say, here's the derivation, let's talk about what it means. Because that's more important. Whenever you see a professor do a derivation in class, he's just wasting time — your time and his. And most of you know it; that's why you fall asleep.
§6. Electron beam welding: high-energy particles in vacuum [39:35]
Why don't we take a break for five minutes and come back — we're going to start late.
Student: [Question about industry investment in spot welding.]
Yes — I think that's right, fifty billion a year. The U.S. automotive industry spends a lot of money on resistance spot welding — billions of dollars a year. Five hundred dollars worth of spot welding in every automobile. It to a certain extent defines a lot of the structural requirements of the car. And it's about a hundred thousand watts per square centimeter equivalent. Now we're going to go to laser and electron beam. People will say, oh, they're high heat intensity processes, they're the same, they're interchangeable. What I'm going to do is contrast them and show you why they're not interchangeable.
The first thing about these two is that with electron beam you heat with electrons; with a laser, you heat with photons. What difference does that make? It makes a lot of difference in a number of cases. Your electron beam machine will typically be somewhere between zero and 60 kilovolts, or 100 kilovolts, or greater. Why? Because if you're hitting a metal surface with electrons of less than 60 kilovolts, you can shield that with window glass, sheet metal. The X-ray radiation coming off is easily shielded by your vacuum chamber. Above 60 kilovolts — getting to 100 kilovolts — you get enough penetrating capability of those X-rays that you have to add lead sheeting to the outside of your vacuum chamber, and that costs money.
Why don't they always use less than 60 kilovolts? In heavier steels you need something like 10 kilowatts to make a weld. I may have mentioned this before, when I talked about particle beam weapons and said they had megawatts of power. You can melt a submarine, but you don't need it — you only need 10 to 100 kilowatts for most heavy-section welds. You don't want more than a tenth of an ampere in your electron beam, and I'll explain why in a second. That's 6 kilowatts. So if you're doing thin sheet material, you can use zero to 60 kilovolt machines — typically 40 to 60 kilovolt is what most people use. Having your part inside a vacuum system is all the radiation shielding you need.
But if you're doing something half an inch thick, you don't have enough power to penetrate when you're limited to a tenth of an amp. Why am I limited to a tenth of an amp? Here's my electron gun, here's my workpiece, and these little electrons are shooting down putting their energy into the workpiece. It's all electron-flow energy — you're in a vacuum, typically. These things are going at essentially the speed of light — relativistic, 99-plus percent, depending on the voltage. You start calculating these currents and how close these electrons are in the beam, and you find if you get up to three-tenths of an amp, the electrons are so close together they start defocusing the beam. The mutual repulsion causes defocusing.
There are plenty of electron beam melting furnaces out there that use three amps, but they have a spot size this big — you don't care about spot size if you're just trying to melt. But if you're trying to weld, you want a very sharp spot, and you can't focus very well above two- or three-tenths of an amp. Most machines are limited to about a tenth of an amp for good focusing. Which means if I want greater than 10 kilowatts, I go to 100 kilovolts so that at a tenth of an amp I can get 10 kilowatts. The Japanese built one at 600 kilovolts and got 60 kilowatts, and were doing electron beam welds in four, five, six, eight inch thick steel. We'll talk about why that didn't work all that well.
I have tremendous radiation at higher voltages, which adds cost because of extra lead sheathing. 100 kilovolts, maybe it's an eighth or 3/16 of an inch of lead. Get to 200 kilovolts, and now you're talking about 3/8 of an inch of lead sheathing around the whole thing. If you have windows, they have to be leaded glass several inches thick.
§7. Arc versus electron beam: voltage, energy, and subsurface deposition [46:07]
Student: What is the major difference between an arc weld and an electron beam weld?
The arc weld is in a gas, in the atmosphere. In an arc weld, we've got one atmosphere of some gas — CO2, helium, argon, oxygen, whatever. The voltage of the electrons going across is 5 volts across this little gas boundary layer. In an electron beam, the energy of the electron is 60,000 or 100,000 electron volts. There it's five electron volts. In arc welding I've got 100 or 200 amps of current; in electron beam, a tenth of an amp, in a vacuum. So it's still electron-flow heating, but you don't have an anode voltage drop because you don't have a gas boundary layer. But you do have the work function voltage.
The energy is mostly the kinetic energy of the electrons. The kT thermal energy in arc welding is one volt. In electron beam it's 60,000 volts or 100,000 volts. Very different electrons in terms of their kinetic energy. Each electron in electron beam welding has enough energy to partially penetrate the surface. I'm going to go through that in a little bit. You're actually depositing your heat slightly beneath the surface. In arc welding it's all deposited right there on the surface. Those electrons can't go more than one atom deep. They might get conducted away once they get in the metal, but that's metal conduction, generating only resistive heat which is insignificant compared to the arc. Does that answer the question?
For electrons, you get finer spot size, and we're going to talk about alignment issues that come with that. Remember on the very first day I talked about these different heat intensities. Once you get to laser and electron beam, you have interaction times, because you have power densities of a million watts per square centimeter — you have to be moving fast. Are you just going to burn a hole through it? You're not going to be welding unless you travel quickly. You're traveling so quickly — remember, I got out the dollar bill and showed you the reaction time. No one can respond in the millisecond it takes to control the weld pool in an electron beam or laser weld. You can't turn the corners to follow the seam quickly enough. You have to have everything automated.
It's a very energy-efficient process — calculations show it's nearly 99 percent. The wall-plug power into your beam — the gun being a hot tungsten filament in a vacuum boiling off electrons in a big electric field — that wall-plug power is near 100 percent efficient. In an arc it's 50 percent because you've got all these hot gases going off to the side wasting energy, heating up the welder. The advantage of an arc is you can run it manually. You don't have to have a big vacuum chamber, you don't have to have automation. Ten thousand dollars worth of equipment to get into the arc welding business. A million dollars worth of equipment to get into the electron beam business.
With electron beam or laser welding, you've got to have very high production volume to keep it busy, or a very high-value-added part. Electron beams and lasers are typically used in automotive, where you have thousands of feet of weld to make lots of parts. To weld the stainless steel clamshell on a catalytic converter, Ford one time went with out-of-vacuum electron beam. They needed six of them to take care of all the production for Ford's catalytic converters. If they had gone with gas tungsten arc welders at a much slower speed, they probably would have needed 200 arcs to do what six electron beam units could do, because of the difference in travel speed. So it's a question of the economics of the equipment.
In that case Ford bought Westinghouse out-of-vacuum electron beam machines, where you generate the beam in a vacuum of about 10⁻⁸ atmospheres, and you have a little aerodynamic window — a continuous leak into your vacuum system — and the beam shoots out into the air. The electron beam has some ability to penetrate air — depending on voltage, maybe a millimeter, maybe five millimeters. Your standoff distance between workpiece and beam, before it defocuses in the air because these electrons hit air atoms and scatter, has to be accurate within a few human hairs or you won't get a consistent weld. The other problem is you've got a continuous leak into your vacuum system, so maintenance on these out-of-vacuum electron beams is horrendous.
There was this guy in the 1980s — actually started in the 1960s, I can't remember his name — but he came from Germany, and he had made a career out of out-of-vacuum electron beam. He got hired by a company in Connecticut, they started selling these machines, and they sold some manager at Ford on them. I talked to one of the guys who was the manager at the plant who had to keep these things operating, and if you just mentioned out-of-vacuum electron beam, he would pull out a knife wanting to kill anyone in the area. It was the biggest headache in the world to maintain. They don't use them anymore. But it has been done. When I worked at Bethlehem Steel in the mid-1970s, I flew to Pittsburgh, to Westinghouse research, and this guy made a weld for us — one pass in three-quarter-inch steel. There are other problems with it.
Typically they're used in automotive — high volume, lots of speed — or aerospace, where the value added per part is huge and you can pay for an expensive machine to get a good weld. They have a lot more precision capability, but they're not the answer to everything, and they are expensive. So it's usually aircraft or automotive. I've seen data on lasers, and virtually 98 percent of welding lasers are automotive or aerospace applications because of these things we're going through.
§8. Lasers versus electron beams, and the Sciaky camshaft case [53:50]
Electron beams have tremendous penetrating capability — we're going to talk about that in the next thing. The laser heats with photons. E equals h nu, where h is Planck's constant and nu is the frequency. You can change that frequency to c over lambda. The wavelength of the laser is somewhere around a micron or 10 microns, depending on whether it's a CO2 laser or YAG laser or whatever. The energy at those wavelengths is on the order of a tenth of an electron volt, not a hundred thousand electron volts like an electron beam. There's a million-fold difference between the particles doing the heating.
There's also a million-fold difference in the number of particles. They've got one-millionth of the energy, but the same energy in the total spot, so I have to have a lot more photons. Photons definitely just heat the top surface. They don't even penetrate one atom deep. They basically interact with the electrons on the surface and are either reflected or absorbed. We'll talk about that in a second. There's a million-fold difference in the energy of what you're hitting the surface with. There are twelve different differences we're going to go through, but the first is you have to understand I'm using different types of particles with a million-fold difference in their energy. Electron beams heat beneath the surface about a tenth of a millimeter. That's only four-thousandths of an inch, a little more than a human hair, but it makes a difference. The laser, all the heat's on the surface — it doesn't even penetrate one atomic distance.
My best example here is actually not a welding issue, it's a heat-treating issue. There's a company in Chicago called Sciaky. Sciaky is a French company originally. There's a Sciaky U.S. in Chicago now. Sciaky came to the United States about 1940 to the Philadelphia Navy Yard. They were just developing gas tungsten arc welding in the world at the time. Sciaky had the best gas tungsten arc welder. The Philadelphia Navy Yard built airplanes out of aluminum, and gas tungsten arc is a great process for welding aluminum. So the Navy brought Sciaky to the United States before the Germans took over everything. Sciaky then set up in the United States.
Sciaky will sell you laser or electron beam systems — million, ten million dollars. They like to sell to Boeing or Ford or GM, because that's the industries you sell this stuff into. Sciaky was asked — I think it might have been Ford, but one of the automotive companies — to harden the surfaces of camshafts. The camshafts have lobes that go spinning around and push the engine valves up or down. As the camshaft rotates, these lobes push the valve down against a spring. So I've got a cylindrical shaft with lobes on it — protrusions, maybe a half inch wide or three-eighths or three-quarters of an inch wide. The lobe comes along as it rotates, hits the top of the valve, which usually has a cap on it, and pushes it down against the spring. That's how the engine gets the valves opening and closing at the right time.
They wanted to heat-treat the surface of the steel camshaft to make it harder. Sciaky built them a system — this is 30 or 35 years ago — using high-power lasers, which were fairly new and sophisticated at the time. No vacuum system required — that's an advantage of lasers. So you save on the vacuum, high-volume automotive, big savings. They decided to use lasers. The problem is, they always got cracking. Why? Since it's all surface heating, the hottest part is right on the surface. As you heat it up — you're not melting it, you're just trying to heat it so you can transform the steel and quench it for hardened steel — it expands. As it expands when hot, what did I tell you about residual stresses? The residual stress is always reverse. If it expands in compression when hot, it'll be in tension when cold.
So they heated the surface of this lobe, ended up with very severe tensile residual stresses, and started getting surface cracks and spalling. The whole process was a disaster. Ten million dollar machine was garbage. So they switched to electron beam, and they had no problem, because electron beam actually deposits the heat about four-thousandths of an inch deep. The hottest area was just beneath the surface. That's where my tensile residual stresses were. I got compressive stresses on the very surface — exactly what you want for the wear on those things. A very successful process. Completely different results. Both high-intensity processes, but because one has high-energy particles and the other doesn't, you get slightly different heating patterns. Only about four-thousandths of an inch, a tenth of a millimeter difference, but it makes a world of difference.